2011-11-23-MaskedBitsCrash.ll 605 B

1234567891011121314151617
  1. ; RUN: opt < %s -instsimplify
  2. ; The mul can be proved to always overflow (turning a negative value
  3. ; into a positive one) and thus results in undefined behaviour. At
  4. ; the same time we were deducing from the nsw flag that that mul could
  5. ; be assumed to have a negative value (since if not it has an undefined
  6. ; value, which can be taken to be negative). We were reporting the mul
  7. ; as being both positive and negative, firing an assertion!
  8. define i1 @test1(i32 %a) {
  9. entry:
  10. %0 = or i32 %a, 1
  11. %1 = shl i32 %0, 31
  12. %2 = mul nsw i32 %1, 4
  13. %3 = and i32 %2, -4
  14. %4 = icmp ne i32 %3, 0
  15. ret i1 %4
  16. }