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LinearInterpolant

duanjobs 6 years ago
parent
commit
cedb12fed9
1 changed files with 11 additions and 11 deletions
  1. 11 11
      docs/api/zh/math/interpolants/LinearInterpolant.html

+ 11 - 11
docs/api/zh/math/interpolants/LinearInterpolant.html

@@ -10,13 +10,13 @@
 	<body>
 		[page:Interpolant] &rarr;
 
-		<h1>[name]</h1>
+		<h1>线性插值([name])</h1>
 
 		<p class="desc">
 
 		</p>
 
-		<h2>Example</h2>
+		<h2>例子(Example)</h2>
 
 		<code>
 var interpolant = new THREE.[name](
@@ -30,19 +30,19 @@ interpolant.evaluate( 0.5 );
 		</code>
 
 
-		<h2>Constructor</h2>
+		<h2>构造函数(Constructor)</h2>
 
 		<h3>[name]( parameterPositions, sampleValues, sampleSize, resultBuffer )</h3>
 		<p>
-		parameterPositions -- array of positions<br />
-		sampleValues -- array of samples<br />
-		sampleSize -- number of samples<br />
-		resultBuffer -- buffer to store the interpolation results.<br /><br />
+		parameterPositions -- 位置数组<br />
+		sampleValues -- 样本数组<br />
+		sampleSize -- 样本数量<br />
+		resultBuffer -- 用于存储插值结果的缓冲区。<br /><br />
 
 
 		</p>
 
-		<h2>Properties</h2>
+		<h2>属性(Properties)</h2>
 
 
 
@@ -71,14 +71,14 @@ interpolant.evaluate( 0.5 );
 
 		</p>
 
-		<h2>Methods</h2>
+		<h2>方法(Methods)</h2>
 
 		<h3>[method:null evaluate]( [param:Number t] )</h3>
 		<p>
-		Evaluate the interpolant at position *t*.
+			评估位置*t*处的插值。
 		</p>
 
-		<h2>Source</h2>
+		<h2>源码(Source)</h2>
 
 		[link:https://github.com/mrdoob/three.js/blob/master/src/[path].js src/[path].js]
 	</body>