Преглед изворни кода

Clarify type inference in ProjectSettings Inferred Declaration warning

Hugo Locurcio пре 1 месец
родитељ
комит
56f355e709
1 измењених фајлова са 1 додато и 1 уклоњено
  1. 1 1
      doc/classes/ProjectSettings.xml

+ 1 - 1
doc/classes/ProjectSettings.xml

@@ -553,7 +553,7 @@
 			When set to [code]warn[/code] or [code]error[/code], produces a warning or an error respectively when a static inferred type uses a [Variant] as initial value, which makes the static type to also be Variant.
 		</member>
 		<member name="debug/gdscript/warnings/inferred_declaration" type="int" setter="" getter="" default="0">
-			When set to [code]warn[/code] or [code]error[/code], produces a warning or an error respectively when a variable, constant, or parameter has an implicitly inferred static type.
+			When set to [code]warn[/code] or [code]error[/code], produces a warning or an error respectively when a variable, constant, or parameter has an implicitly inferred static type. In GDScript, type inference is performed by declaring a variable with [code]:=[/code] instead of [code]=[/code] and leaving out the type specifier. For example, [code]var x := 1[/code] will [i]infer[/i] the [int] type, while [code]var x: int = 1[/code] explicitly declares the variable as [int].
 			[b]Note:[/b] This warning is recommended [i]in addition[/i] to [member debug/gdscript/warnings/untyped_declaration] if you want to always specify the type explicitly. Having [code]INFERRED_DECLARATION[/code] warning level higher than [code]UNTYPED_DECLARATION[/code] warning level makes little sense and is not recommended.
 		</member>
 		<member name="debug/gdscript/warnings/int_as_enum_without_cast" type="int" setter="" getter="" default="1">