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Fix class name : change "string" to "String"

Change case of "s" letter : "string" does not compile but "String" does (for gdScript)

(cherry picked from commit 55b63eceaa22f979bd40656fb8444cc94a7942b7)
dtesniere 3 lat temu
rodzic
commit
ed4e597027
1 zmienionych plików z 1 dodań i 1 usunięć
  1. 1 1
      doc/classes/Dictionary.xml

+ 1 - 1
doc/classes/Dictionary.xml

@@ -31,7 +31,7 @@
 		[/codeblock]
 		You can access a dictionary's values by referencing the appropriate key. In the above example, [code]points_dict["White"][/code] will return [code]50[/code]. You can also write [code]points_dict.White[/code], which is equivalent. However, you'll have to use the bracket syntax if the key you're accessing the dictionary with isn't a fixed string (such as a number or variable).
 		[codeblock]
-		export(string, "White", "Yellow", "Orange") var my_color
+		export(String, "White", "Yellow", "Orange") var my_color
 		var points_dict = {"White": 50, "Yellow": 75, "Orange": 100}
 		func _ready():
 		    # We can't use dot syntax here as `my_color` is a variable.