[3.x] Correctly calculate position of the folding arrow in `Tree`
@@ -1404,7 +1404,10 @@ int Tree::draw_item(const Point2i &p_pos, const Point2 &p_draw_ofs, const Size2
arrow = cache.arrow;
}
- arrow->draw(ci, p_pos + p_draw_ofs + Point2i(0, (label_h - arrow->get_height()) / 2) - cache.offset);
+ Point2 apos = p_pos + Point2i(0, (label_h - arrow->get_height()) / 2) - cache.offset + p_draw_ofs;
+ apos.x += cache.item_margin - arrow->get_width();
+
+ arrow->draw(ci, apos);