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Эх сурвалжийг харах

Minor fix in DrawLineBezier* (#3006)

When `i` starts with `0`, `t` is also `0`, which results in `previous == startPos == current`, this segment is not only redundant, but it also causes division-by-zero since `sqrtf(dx*dx + dy*dy)` is zero.
eternalStudent 2 жил өмнө
parent
commit
8f741d894a
1 өөрчлөгдсөн 2 нэмэгдсэн , 2 устгасан
  1. 2 2
      src/rshapes.c

+ 2 - 2
src/rshapes.c

@@ -241,7 +241,7 @@ void DrawLineBezierQuad(Vector2 startPos, Vector2 endPos, Vector2 controlPos, fl
 
     Vector2 points[2*BEZIER_LINE_DIVISIONS + 2] = { 0 };
 
-    for (int i = 0; i <= BEZIER_LINE_DIVISIONS; i++)
+    for (int i = 1; i <= BEZIER_LINE_DIVISIONS; i++)
     {
         t = step*i;
         float a = powf(1 - t, 2);
@@ -286,7 +286,7 @@ void DrawLineBezierCubic(Vector2 startPos, Vector2 endPos, Vector2 startControlP
 
     Vector2 points[2*BEZIER_LINE_DIVISIONS + 2] = { 0 };
 
-    for (int i = 0; i <= BEZIER_LINE_DIVISIONS; i++)
+    for (int i = 1; i <= BEZIER_LINE_DIVISIONS; i++)
     {
         t = step*i;
         float a = powf(1 - t, 3);